Trigonometry in 3 dimensions - Higher
Discover updated revision resources for GCSE Maths: Trigonometry in 3D, with step-by-step slideshows, quizzes, practice exam questions, and more!
The trigonometric ratios can be used to solve An object with width, height and depth, eg a cube. problems which involve calculating a length or an angle in a right-angled triangle.
It may be necessary to use Pythagoras' theorem and trigonometry to solve a problem.
Example
The shape ABCDEFGH is a cuboid.
Length AB is 6 cm, length BG is 3 cm and length FG is 2 cm.
The length of the diagonal AF is 7 cm.
Calculate the angle between AF and the A flat, two-dimensional surface. ABCD. Give the answer to 3 significant figures.
The plane ABCD is the base of the cuboid. The line FC and the plane ABCD form a right angle.
Draw the right-angled triangle AFC and label the sides. The angle between AF and the plane is \(x\).
Use \(\sin{x} = \frac{o}{h}\)
\(\sin{x} = \frac{3}{7}\)
\(\sin{x} = 0.428571 \dotsc\). Do not round this answer yet.
To calculate the angle use the inverse sin button on the calculator (\(\sin^{-1}\)).
\(x = 25.4^\circ\)
Question
The shape ABCDV is a square-based A base with triangular faces meeting at a a point called an apex.. O is the midpoint of the square base ABCD.
Lengths AD, DC, BC and AB are all 4 cm.
The If the angle between two lines is a right angle, the lines are said to be perpendicular. height of the pyramid (OV) is 3 cm.
Calculate the angle between VC and the plane ABCD. Give the answer to 3 significant figures.
The plane ABCD is the base of the pyramid. The line VO and the plane ABCD form a right angle.
Draw the right-angled triangle OVC and label the sides. The angle between VC and the plane is \(y\).
It is not possible to use trigonometry to calculate the angle \(y\) because the length of another side is required.
Pythagoras can be used to calculate the length OC.
Draw the right-angled triangle ACD and label the sides.
\(a^2 + b^2 = c^2\)
\(\text{CD}^2 + \text{AD}^2 = \text{AC}^2\)
\(4^2 + 4^2 = AC^2\)
\(32 = AC^2\)
\(AC = \sqrt{32}\)
\(\sqrt{32} \) is a surd. Do not round this answer yet.
The length AC is \(\sqrt{32}\) cm.
The point O is in the centre of the length AC so OC is half of the length AC.
The length OC is \(\frac{\sqrt{32}}{2}\) cm.
Use \(\tan{x} = \frac{o}{a}\)
\(\tan{x} = \frac{3}{\frac{\sqrt{32}}{2}}\)
\(\tan{x} = 1.06066 \dotsc\). Do not round this answer yet.
To calculate the angle use the inverse tan button on the calculator (\( \tan^{-1}\)).
\(x = 46.7^\circ\)
More guides on this topic
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- NEW: Polygons
- NEW: Line and rotational symmetry
- NEW: Constructing triangles
- NEW: Ruler and compass constructions
- NEW: Loci
- NEW: Bearings
- NEW: Perimeter
- NEW: Area
- NEW: Volume of a prism
- NEW: Surface area of a prism
- NEW: Pyramids, cones and spheres
- NEW: Nets, plans and elevations
- NEW: Circumference and arc length
- NEW: Area of circles and sectors
- NEW: Higher – Circle Theorems – Calculating angles using circles
- NEW: Higher – Using the alternate segment theorem, tangents and chords
- NEW: Reflection
- NEW: Rotation
- NEW: Translation
- NEW: Enlargement
- NEW: Higher − Negative enlargements
- NEW: Higher – Combined transformations and invariant points
- NEW: Congruent and similar shapes
- NEW: Higher – Similarity in 2D and 3D shapes
- NEW: Pythagoras' theorem
- NEW: Solving 2D and 3D problems using Pythagoras' theorem
- NEW: Right-angled trigonometry
- NEW: Exact trigonometric values
- NEW: Higher – Sine rule
- NEW: Higher – Cosine rule
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- NEW: Vectors
- NEW: Higher – Geometric problems using vectors
- Angles, lines and polygons - Edexcel
- Loci and constructions - Edexcel
- Circles, sectors and arcs - Edexcel
- Circle theorems - Higher - Edexcel
- Pythagoras' theorem - Edexcel
- Units of measure - Edexcel
- Vectors - Edexcel
