Inertia and momentum – Higher
Inertia
The only way to change the velocityThe speed of an object in a particular direction. of an object is to apply a force over a period of time.
In some cases, it takes a long time to change the velocity significantly. In these cases, the object seems reluctant to have it’s speed changed.
The tendency of an object to continue in its current state (at rest or in uniform velocity) is called inertiaThe tendency of an object to continue in its current state (at rest or in uniform motion) unless acted on by a resultant force..
All objects have inertia. Whether they are moving or not.
Inertial mass
The ratio of force over acceleration is called inertial massA measure of how difficult it is to change the velocity of an object. It is defined as the ratio of force over acceleration.. Inertial mass is a measure of how difficult it is to change the velocity of an object. The inertial mass can be measured using this rearrangement of Newton's second law:
\(\text{m} = \frac{\text{F}}{\text{a}}\)
Momentum
momentumA quantity relating to a moving object that is calculated by multiplying its mass by its velocity. is a property of moving objects and is useful when analysing collisions.
Momentum is the product of massThe amount of matter an object contains. Mass is measured in kilograms (kg) or grams (g). and velocity. Momentum is also a vectorA vector describes a movement from one point to another. A vector quantity has magnitude (size) and direction. quantity – this means it has both a magnitudeThe size of a physical quantity. and an associated direction.
For example, an elephant has no momentum when it is standing still. When it begins to walk, it will have momentum in the same direction as it is travelling. The faster the elephant walks, the larger its momentum will be.
Learn more on momentum in this podcast
Listen to the full series on BBC Sounds.
Calculating momentum
Momentum can be calculated using the equation:
momentum = mass × velocity
\(\text{p} = \text{mv}\)
This is when:
- momentum (\(\text{p}\)) is measured in kilogram metres per second (kg m/s)
- velocity (\(\text{v}\)) is measured in metres per second (m/s)
- mass (\(\text{m}\)) is measured in kilograms (kg)
Example
A lorry has a mass of 7,500 kg. It travels south at a speed of 25 m/s. Calculate the momentum of the lorry.
\(\text{p} = \text{mv}\)
= 7,500 × 25
= 187,500 kg m/s (south)
Question
An ice skater has a mass of 60 kg and travels at a speed of 15 m/s. Calculate the momentum of the skater.
\(\text{p} = \text{mv}\)
= 60 × 15
= 900 kg m/s
Conservation of momentum
In a closed system:
total momentum before an event = total momentum after the event
A 'closed system' is something that is not affected by external forces. This is called the principle of conservation of momentumThe principle that the total momentum of a system remains the same. When bodies collide, whatever momentum is lost by one body, the other gains in equal amounts.. Momentum is conserved in collisionWhen two objects meet and interact, eg two particles moving towards each other will collide. and explosionWhen parts of a system separate and move apart. For example, a supernova is an exploding star - the outer layers are thrown out into space in all directions..
Conservation of momentum explains why a gun or cannon recoils backwards when it is fired. When a cannon is fired, the cannon ball gains forward momentum and the cannon gains backward momentum. Before the cannon is fired (the 'event'), the total momentum is zero. This is because neither object is moving. The total momentum of the cannon and the cannon ball after being fired is also zero, with the cannon and cannon ball moving in opposite directions.
Calculations involving collisions
Collisions are often investigated using small trolleys. The following diagrams show an example.
Image caption, Before collision
Image caption, After collision
1 of 2
You can use the principle of conservation of momentum to calculate the velocity of the combined trolleys after the collision.
Example calculation
Calculate the velocity of the trolleys after the collision in the example above.
First calculate the momentum of both trolleys before the collision:
2 kg trolley = 2 × 3 = 6 kg m/s
4 kg trolley = 8 × 0 = 0 kg m/s
Total momentum before collision = 6 + 0 = 6 kg m/s
Total momentum (p) after collision = 6 kg m/s (because momentum is conserved)
Mass (\(\text{m}\)) after collision = 10 kg
Next, rearrange \(\text{p} = \text{mv}\) to find \(\text{v}\):
\(\text{v} = \frac{\text{p}}{\text{m}}\)
= 6 ÷ 10
= 0.6 m/s
Note that the 2 kg trolley is travelling to the right before the collision. As its velocity and the calculated velocity after the collision are both positive values, the combined trolleys must also be moving to the right after the collision.
More guides on this topic
- Motion - AQA Synergy
- Circuits - AQA Synergy
- Mains electricity - AQA Synergy
- Acids and alkalis - AQA Synergy
- Rates of reaction - AQA Synergy
- Energy, rates and reactions - AQA Synergy
- Equilibria - AQA Synergy
- Electrons and chemical reactions - AQA Synergy
- Sample exam questions - movement and interactions - AQA Synergy