Product rule - Higher
To find the total number of outcomes for two or more events, multiply the number of outcomes for each event together. This is called the product rule because it involves multiplying to find a product.
Example
A restaurant menu offers 4 starters, 7 main courses and 3 different desserts. How many different three-course meals can be selected from the menu?
Multiplying together the number of choices for each course gives \(4 \times 7 \times 3 = 84\) different three-course meals.
Sample space diagrams
Sample space diagrams are a visual way of recording the possible outcomes of two events, which can then be used to calculate probabilityThe extent to which something is likely to be the case..
Two-way tables show the outcomes of one event in the top row and of another event in the first column.
Example
Two dice are rolled at the same time and their scores are added together. Find the probabilityThe extent to which something is likely to be the case. of the sumTo add. The sum of 8 and 4 is 12 as 8 + 4 = 12. of the two dice equalling 7.
Below is a table with the outcomes of rolling die 1 in the top row and die 2 in the first column.
| + | 1 | 2 | 3 | 4 | 5 | 6 |
| 1 | 1 + 1 = 2 | 1 + 2 = 3 | 1 + 3 = 4 | 1 + 4 = 5 | 1 + 5 = 6 | 1 + 6 = 7 |
| 2 | 2 + 1 = 3 | 4 | 5 | 6 | 7 | 8 |
| 3 | 4 | 5 | 6 | 7 | 8 | 9 |
| 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| 5 | 6 | 7 | 8 | 9 | 10 | 11 |
| 6 | 7 | 8 | 9 | 10 | 11 | 12 |
| 1 | |
|---|---|
| 1 | 1 + 1 = 2 |
| 2 | 1 + 2 = 3 |
| 3 | 1 + 3 = 4 |
| 4 | 1 + 4 = 5 |
| 5 | 1 + 5 = 6 |
| 6 | 1 + 6 = 7 |
| 2 | |
|---|---|
| 1 | 2 + 1 = 3 |
| 2 | 4 |
| 3 | 5 |
| 4 | 6 |
| 5 | 7 |
| 6 | 8 |
| 3 | |
|---|---|
| 1 | 4 |
| 2 | 5 |
| 3 | 6 |
| 4 | 7 |
| 5 | 8 |
| 6 | 9 |
| 4 | |
|---|---|
| 1 | 5 |
| 2 | 6 |
| 3 | 7 |
| 4 | 8 |
| 5 | 9 |
| 6 | 10 |
| 5 | |
|---|---|
| 1 | 6 |
| 2 | 7 |
| 3 | 8 |
| 4 | 9 |
| 5 | 10 |
| 6 | 11 |
| 6 | |
|---|---|
| 1 | 7 |
| 2 | 8 |
| 3 | 9 |
| 4 | 10 |
| 5 | 11 |
| 6 | 12 |
The sample space diagram shows there are 6 ways of making a 7, out of a total of 36 possible combinations.
Therefore, the probability of rolling two dice and the sum being 7 is \(\frac{6}{36}\) = \(\frac{1}{6}\).
