Specific heat capacity
Heating materials
When materials are heated, the moleculeA collection of two or more atoms held together by chemical bonds. gain kinetic energyEnergy which an object possesses by being in motion. and start moving faster. The result is that the material gets hotter.
Different materials require different amounts of energy to change temperature. The amount of energy needed depends on:
- the mass of the material
- the substance of the material (specific heat capacityThe amount of energy needed to raise the temperature of 1 kg of substance by 1°C.)
- the desired temperature change
It takes less energy to raise the temperature of a block of aluminium by 1°C than it does to raise the same amount of water by 1°C. The amount of energy required to change the temperature of a material depends on the specific heat capacity of the material.
Learn more about specific heat capacity in this podcast
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Heat capacity
The specific heat capacity of water is 4,200 Joules per kilogram per degree Celsius (J/kg°C). This means that it takes 4,200 J to raise the temperature of 1 kg of water by 1°C.
Some other examples of specific heat capacities are:
| Material | Specific heat capacity (J/kg/°C) |
| Brick | 840 |
| Copper | 385 |
| Lead | 129 |
| Material | Brick |
|---|---|
| Specific heat capacity (J/kg/°C) | 840 |
| Material | Copper |
|---|---|
| Specific heat capacity (J/kg/°C) | 385 |
| Material | Lead |
|---|---|
| Specific heat capacity (J/kg/°C) | 129 |
Lead will warm up and cool down fastest because it doesn’t take much energy to change its temperature. Brick will take much longer to heat up and cool down. This is why bricks are sometimes used in storage heaters as they stay warm for a long time. Most heaters are filled with oil (1,800 J/kg°C) or water (4,200 J/kg°C) as these emit a lot of energy as they cool down and, therefore, stay warm for a long time.
Calculating thermal energy changes
The amount of thermal energyA more formal term for heat energy. stored or released as the temperature of a system changes can be calculated using the equation:
change in thermal energy = mass × specific heat capacity × temperature change
\(\Delta E_{t}=m \times c \times \Delta \Theta\)
This is when:
- change in thermal energy (ΔEt) is measured in joules (J)
- mass (m) is measured in kilograms (kg)
- specific heat capacity (c) is measured in joules per kilogram per degree Celsius (J/kg°C)
- temperature change (∆θ) is measured in degrees Celsius (°C)
Example
Sadie is experimenting with a model steam engine. Before the 0.25 kg of water begins to boil it needs to be heated from 20°C up to 100°C. If the specific heat capacity of water is 4,180 J/kg°C, how much thermal energy is needed to get the water up to boiling point?
\(E_{t} = m~c~\Delta \theta\)
\(E_{t} = 0.25 \times 4,180 \times (100 - 20)\)
\(E_{t} = 0.25 \times 4,180 \times 80\)
\(E_{t} = 83,600~J\)
Question
How much thermal energy does a 2 kg steel block (c = 450 J/kg°C) lose when it cools from 300°C to 20°C?
\(E_{t} = m~c~\Delta \theta\)
\(E_{t} = 2 \times 450 \times (300 - 20)\)
\(E_{t} = 2 \times 450 \times 280\)
\(E_{t} = 252,000 J\)
Question
How hot does a 3.5 kg brick get if it’s heated from 20°C by 20,000 J (20 kJ)?
\(\Delta E = m \times c \times \Delta \theta\)
\(\Delta E = \frac{\Delta E}{m \times c}\)
\(\Delta \theta = \frac{20,000}{3.5 \times 840}\)
\(\Delta \theta = 6.8°C\)
final temperature = starting temperature + change in temperature
final temperature = 20+6.8
final temperature = 26.8°C