Further examples for Higher tier
Example 1
If you increase an amount by 10%, then decrease the new amount by 10%, what is the percentage change?
Solution
Let’s try an amount first, such as £100.
Method 1: The Multiplier Method
If we are increasing by 10% the multiplier would be × 1.10
We are then decreasing this by 10% so multiplier here is × 0.90
Combining them 1.10 × 0.90 = 0.99
This means there would be a 1% decrease, or it would be 99% of the original amount.
Method 2
10% of £100 = £10
£100 + £10 = £110
Now decrease this by 10%.
10% of £110 = £11
£110 − £11 = £99
Overall change:
£100 − £99 = £1 and this is 1% of £100.
Method 3
To be more mathematically formal, we could use a letter such as \(\text {x}\)
10% of \(\text {x}\) = 0.1\(\text {x}\)
\(\text {x}\) + 0.1\(\text {x}\) = 1.1\(\text {x}\)
Now decrease this by 10%.
10% of 1.1\(\text {x}\) = 0.11\(\text {x}\)
1.1\(\text {x}\) − 0.11\(\text {x}\) = 0.99\(\text {x}\)
Overall change:
\(\text {x}\) − 0.99\(\text {x}\) = 0.01\(\text {x}\) and this is 1% of \(\text {x}\)
Example 2
What happens if you increase an amount by 100%, then decrease the result by 100%?
Solution
Method 1
For a 100% increase the multiplier would be × 2.00
For a 100% decrease the multiplier would be × 0.00
Combining them 2 × 0 = 0
Method 2
100% of £100 = £100
£100 + £100 = £200
Now decrease this by 100%.
100% of £200 = £200
£200 − £200 = £0
Overall change:
£100 − £0 = £100 and this is 100% of £100
So the outcome doesn’t work in quite the same way for 100%.
Example 3
The value of an investment fell by 11% for two years in a row then went up by 11% for two years in a row.
- If it was originally worth £4,800, how much was it worth after the four years?
- What is the amount lost or gained?
- What would happen if the decreases and increases were reversed?
Solution 1
At the start, it was worth £4,800
The value fell by 11% for two years in a row, so it was then worth:
£4800 × 0.892 = £3,802.08
It then went up by 11% for two years in a row, so it was then worth:
£3802.08 × 1.112 = £4684.542768 = £4,684.54 (to the nearest penny).
The investment worth £4,800 originally is worth £4,684.54 after four years.
Solution 2
Actual change:
£4,800 − £4,684.54 = −£115.46
This is a loss of £115.46
Solution 3
If the losses and gains are reversed:
At the start it was worth £4,800
The value rose by 11% for two years in a row, so it was then worth:
£4,800 × 1.112 = £5,914.08
It then went down by 11% for two years in a row, so it was then worth:
£5,914.08 × 0.892 = £4,684.542768 = £4,684.54 (to the nearest penny).
This is exactly the same as the first case so the investment worth £4,800 originally is worth £4,684.54 after four years.
Method
You can demonstrate the fact there is no change by using the multipliers in one step.
Down 11% for two years: multiplier = × 0.892
Up 11% for two years: multiplier = × 1.112
If the value goes down first, then up: 4800 × 0.892 × 1.112
If the value goes up first, then down: 4800 × 1.112 × 0.892
Therefore:
× 0.892 × 1.112 = × 1.112 × 0.892
Question
All CDs are reduced by 40% on Christmas Eve and then a further 20% on Boxing Day. The Jingle Ball CD usually costs £14. How much does it cost on Christmas Eve and how much on Boxing Day?
Christmas Eve price
- £14 ÷ 100 × 40 = £5.60 reduction
- £14 – £5.60 = £8.40
Boxing Day price
- £8.40 ÷ 100 × 20 = £1.68 reduction
- £8.40 – £1.68 = £6.72
There is an alternative way of calculating this.
Christmas Eve price is reduced by 40% which means that the reduced price is 60% of the original price.
60% of £14 = £14 ÷ 100 × 60 = £8.40
Boxing Day price is reduced by 20% which means that the reduced price is 80% of the Christmas Eve price.
80% of £8.40 = £8.40 ÷ 100 × 80 = £6.72
Whichever way is used, It is important to notice that reducing the price by 40% and then 20% is not the same as making a 60% reduction.