Factorising - Intermediate & Higher tier – WJECMore than one common factor

Factorising is a way of writing an expression as a product of its factors using brackets. We do this by taking out any factors that are common to every term in the expression.

Part ofMathsAlgebra

More than one common factor

For some expressions, a combination of letters and numbers will make up the highest common factor.

Example one

Factorise \(\text{4x}^{2} + \text{2x}\)

It can be helpful to look at the numbers and the letters separately.

The HCF of 4 and 2 is 2.

The HCF of \(\text{x}^{2}\) and \(\text{x}\) is \(\text{x}\).

So the highest common factor of \(\text{4x}^{2}\) and \(\text{2x}\) must be \(\text{2x}\).

\(\text{4x}^{2} ÷ \text{2x = 2x}\)

\(\text{2x} ÷ \text{2x = 1}\)

This gives \(\text{2x(2x + 1)}\)

Example two

Factorise \(\text{6a}^{2} - \text{9a}^{3}\)

The HCF of 6 and 9 is 3.

The HCF of \(\text{a}^{2}\) and \(\text{a}^{3}\) is \(\text{a}^{2}\).

So the highest common factor of \(\text{6a}^{2}\) and \(\text{9a}^{3}\) is \(\text{3a}^{2}\).

\(\text{6a}^{2} ÷ \text{3a}^{2} = \text{2}\)

\(\text{9a}^{3} ÷ \text{3a}^{2} = \text{3a}\)

This gives \(\text{3a}^{2} \text{(2 - 3a)}\)

Question

Factorise \({16c^2} - {24c}\)