Six-mark questions
Six-mark questions are extended open response questions. These require longer answers than the structured questions with fewer marks. It is wise to plan your answer rather than rushing straight into it, otherwise you may stray away from the key points.
Six-mark questions are marked using a levels-based mark scheme because they are open ended. To gain full marks, you need to:
- support explanations using scientific knowledge and understanding
- use appropriate scientific words and terms
- write clearly, linking ideas in a logical way
- maintain a sustained line of reasoning, rather than getting lost or bogged down
You are likely to see command words such as:
- 'describe' - you need to give an account but no reason
- 'explain' - you must give reasons or explanations
- 'devise' - you must plan or invent a procedure using your scientific knowledge and understanding
- 'evaluate' - you must review information, including identifying strengths and weaknesses, and make a supported conclusion
Six-mark questions may be synoptic questions. These questions bring together ideas from two or more topics. For example, a question about atoms could include ideas about atomic structure, isotopes, radiation and nuclear reactions.
Remember that the topics covered in the first paper are assumed knowledge for the second paper, so questions in the second paper may need knowledge and understanding of those topics too.
The answers shown here give marking points as bullet points. You do not usually need to include all of them to gain six marks, but you do need to write in full sentences, linking them logically and clearly.
Writing six-mark answers with Dr Alex Lathbridge
Listen to the full series on BBC Sounds.
How to write six-mark answers in your science GCSE exams.
Sample question 1 - Foundation
Question
Daisy uses her remote controlled model car.
Look at the simple distance-time graph for this car.
Describe and compare, in detail, the distances moved, and the speeds of her car during the six second journey. [6 marks]
OCR Gateway Science, GCE Physics, Paper B751, June 2013.
The car travels at a steady speed for two seconds and travels for 8 m. The car is then stationary for two seconds. Finally, the car moves at a steady speed for two seconds and travels 12 m.
Calculations:
speed = distance ÷ time
In the first two seconds speed = 8 ÷ 2 = 4 m/s
When the car is stationary speed = 0 m/s
In the last two second speed = 12 ÷ 2 = 6 m/s
So the speed is slower in the first two seconds than in the last two seconds.
Answering tip: Briefly plan the key points you want to include in your answer. For example:
- write down what happens at each stage (stationary, steady speed or accelerating)
- calculate one or more speeds (speed = distance ÷ time)
Sample question 2 - Higher
Question
A skydiver jumps from an aeroplane, falls towards the ground, opens their parachute and falls safely to earth.
Use ideas about forces to explain the motion during their jump. [6 marks]
OCR Gateway Science, GCE Physics, Paper J249, 2016 - Higher.
At the start, speed increases so drag also increases. Because the drag increases, the resultant force decreases and acceleration is reduced. When the drag equals the weight of the parachutist, she moves at terminal velocity.
When she opens the parachute, the drag becomes larger than the weight. The larger resultant forces causes a high deceleration until she reaches a lower terminal velocity.
Answering tip: Briefly plan the key points you want to include in your answer. For example:
- say why the speed increases during the first part
- say why acceleration reduces during the first part
- say why speed decreases then stays the same in the second part - parachute opens
Sample question 3 - Higher
Question
Nina and Matt like to ice skate.
Nina and Matt start from rest and hold each other’s hands.
Then they push each other and move apart.
| Person | Mass (kg) before | Velocity (m/s) before | Mass (kg) after | Velocity (m/s) after |
| Nina | 60 | 0 | 60 | -5 |
| Matt | 100 | 0 | 100 | 3 |
| Person | Nina |
|---|---|
| Mass (kg) before | 60 |
| Velocity (m/s) before | 0 |
| Mass (kg) after | 60 |
| Velocity (m/s) after | -5 |
| Person | Matt |
|---|---|
| Mass (kg) before | 100 |
| Velocity (m/s) before | 0 |
| Mass (kg) after | 100 |
| Velocity (m/s) after | 3 |
Explain why Nina and Matt move apart at different velocities.
Use the data and ideas about forces and momentum in your answer. [6 marks]
OCR Gateway Science, GCE Physics, Paper B752, June 2014 - Higher.
The forces between Nina and Matt are equal and opposite. Each of them has the same momentum, because momentum is conserved when they push each other apart. Because Matt has more mass than Nina the same force produces higher acceleration on Nina.
Calculations:
momentum = mass × velocity
Total momentum before = 0 kg m/s
Nina's momentum after = 60 × (-5) = -300 kg m/s
Matt's momentum after = 100 × 3 = 300 kg m/s
Total momentum after = -300 + 300 = 0 kg m/s
Answering tip: Briefly plan the key points you want to include in your answer. For example:
- conservation of momentum
- outline why Nina moves away more quickly than Matt
- use values to calculate total momentum before and after
More guides on this topic
- Quiz: Scalar and vector quantities
- Quiz: Moments, levers and gears
- Quiz: Momentum - Higher
- Scalar and vector quantities - OCR Gateway
- Motion - OCR Gateway
- Newton's laws - OCR Gateway
- Momentum, work and power - OCR Gateway
- Forces and elasticity - OCR Gateway
- Mass, weight and gravitational field strength - OCR Gateway
- Moments, levers and gears - OCR Gateway
- Pressure - OCR Gateway