Bond energy calculations
You can calculate the energy change in a reaction using average bond energies. Bond energy is the amount of energy needed to break one moleThe amount of substance that contains the same number of particles as there are atoms in 12 g of carbon-12 (contains the Avogadro's constant 6.0 ×10²³ number of particles). of a particular bond.
To calculate bond energy
- Add together the bond energies for all the bonds in the reactantA substance that reacts together with another substance to form products during a chemical reaction. – this is the ‘energy in’.
- Add together the bond energies for all the bonds in the productA substance formed in a chemical reaction. – this is the ‘energy out’.
- Calculate the energy change = energy in – energy out.
Worked example – an exothermic reaction
Hydrogen and chlorine react to form hydrogen chloride gas:
H−H + Cl−Cl → 2 × (H−Cl)
| Bond | Bond energy (kJ/mol) |
| H−H | 436 |
| Cl−Cl | 243 |
| H−Cl | 432 |
| Bond | H−H |
|---|---|
| Bond energy (kJ/mol) | 436 |
| Bond | Cl−Cl |
|---|---|
| Bond energy (kJ/mol) | 243 |
| Bond | H−Cl |
|---|---|
| Bond energy (kJ/mol) | 432 |
- Energy in = 436 + 243 = 679 kJ/mol (this is the energy absorbed when the bonds of the reactants break).
- Energy out = 2 × 432 = 864 kJ/mol (this is the energy released when the bonds of the products form).
- Energy change = in – out = 679 – 864 = –185 kJ/mol
The energy change is negative, due to the fact that the energy released by the bonds formed is greater than the energy absorbed by the bonds broken. This means that energy is released to the surroundings in an exothermicReaction in which energy is given out to the surroundings. The surroundings then have more energy than they started with so the temperature increases.reaction.
Worked example – calculating bond energy [Higher tier only]
Hydrogen reacts with iodine to form hydrogen iodide.
H−H + I−I → 2 × (H–I)
| Bond | Bond Energy (kJ/mol) |
| H−I | ? |
| H−H | 436 |
| I−I | 151 |
| Bond | H−I |
|---|---|
| Bond Energy (kJ/mol) | ? |
| Bond | H−H |
|---|---|
| Bond Energy (kJ/mol) | 436 |
| Bond | I−I |
|---|---|
| Bond Energy (kJ/mol) | 151 |
The energy change for this reaction is –3 kJ/mol. Calculate the bond energy of the H–I bond.
- Energy in = 436 + 151 = 587 kJ/mol
- Energy out = 2 × (bond energy of H–I) = 2(H–I)
- Energy change = in – out = 587 – 2(H–I) = –3 kJ/mol
- Rearrange to: 2(H–I) = 587 + 3 = 590 kJ/mol
- Therefore: (H–I) = 590 ÷ 2 = 295 kJ/mol