3-dimensional shapes - AQAComposite volumes and surface areas

Total volume of the salt shaker = \(\text{volume of cylinder} + \text{volume of hemisphere}\)

Volume of cylinder = \( \pi r^2 h = \pi \times 1.5^2 \times 5\)

Volume of a hemisphere = \(\frac{1}{2} \times \frac{4}{3} \times \pi r^3 = \frac{1}{2} \times \frac{4}{3} \times \pi \times 1.5^3\)

Total volume of the salt shaker = \(\pi \times 1.5^2 \times 5 + \frac{1}{2} \times \frac{4}{3} \times \pi \times 1.5^3 = 42.4~\text{cm}^3\)

Total surface area of the salt shaker = \(\text{surface area of cylinder} + \text{surface area of hemisphere}\)

Surface area of cylinder (note only one circular end) = \(\pi r^2 + 2\pi rh = \pi \times 1.5^2 + 2 \times \pi \times 1.5 \times 5\).

Curved surface area of hemisphere = \(\frac{1}{2} \times 4\pi r^2 = \frac{1}{2} \times 4 \times \pi \times 1.5^2\).

Total surface area of the salt shaker = \(\pi \times 1.5^2 + 2 \times \pi \times 1.5 \times 5 + \frac{1}{2} \times 4 \times \pi \times 1.5^2 = 68.3~cm^2\)