When you know the value for letters in an algebraic expression you can substitute these values into the expression and solve it.
Part ofMathsExpressions and equations
Now try these two questions:
If \(a~=~4\) and \(b~=~7\)
Find \(5~a~+~b\)
\(5~×~4~+~7\)
\(=~20~+~7\)
\(=~27\)
If \(x~=~-5\) and \(y~=~-1\)
Find \(x~+~y\)
\((-5)~+~(-1)\)
\(=~-~5~-~1\)
\(=~-6\)
