Substitution of negative numbers
A formula may be given using letters:
P = 3A + 2T
- 3A means 3 × A
- 2T means 2 × T
Example 1
Use the formula D = 2B + 4C to find the value of D when B = 5 and C = 3.
1. Write in the meaning of 2B (2 × B) and 4C (4 × C):
D = 2 × B + 4 × C.
2. Replace the letters with the values you are given:
D = 2 × 5 + 4 × 3.
3. Remember BIDMAS (multiply first then add):
D = 10 + 12.
D = 22.
Example 2
Use the formula Y = 2Z + 4W when Z = 7 and W = -2.
1. Write in the meanings of 2Z and 4W:
Y = 2 × Z + 4 × W.
2. Replace the letters with the values you are given:
Y = 2 × 7 + 4 × -2.
3. Do the multiplication sums. Don’t forget the rules with negative numbers. In this case, a positive multiplied by a negative make a negative:
Y = 14 + -8.
4. Complete the sum. Don’t forget a plus and a minus make a minus:
Y = 14 - 8.
Y = 6.
Question
Given that F = 8L - 5K, find the value of F when L = 9 and K = -4.
F = 8 × L - 5 × K
F = 8 × 9 - 5 × -4
F = 72 + 20 (A negative multiplied by a negative makes a positive.)
F = 92
Example 3 - Higher tier
Use the formula Q = 2R - 3S to find the value of R when Q = -30 and S = 4.
1. Replace the known letters:
-30 = 2 × R - 3 × 4.
2. Multiply:
-30 = 2 × R - 12.
3. Add 12 to both sides:
-30 + 12 = 2 × R.
-18 = 2 × R.
4. Divide both sides by 2:
-18 ÷ 2 = R.
R = -9.
Question
Given that R = 2B + 4C, find the value of C when R = 20 and B = -3.
20 = 2 × -3 + 4 × C
20 = -6 + 4 × C
20 + 6 = 4 × C
26 = 4 × C
26 ÷ 4 = C
6.5 = C
Example 4 - Higher tier
In equations and formulae, division is usually presented as a fraction, eg:
\({S}=\frac{{2F}-{3H}}{4}\)
Question
Find the value of S when F = 10 and H = -2.
\({S}=\frac{{{2}\times{10}}-{{3}\times{2}}}{4}\)
\({S}=\frac{{20}+{6}}{4}\)
\({S}=\frac{26}{4}\)
\({S}={6.5}\)
Question
Find the value of F when H = -2 and S = -4.
F = -11
\({-4}=\frac{{{2}\times{F}}-{{3}\times{-2}}}{4}\)
\({-4}\times{4}~{=}~{2}\times{F}~{+}~{6}\)
\({-16}~{=}~{2}\times{F}~{+}~{6}\)
\({-16}~{-6}~{=}~{2}\times{F}\)
\({-22}~{=}~{2}\times{F}\)
\(\frac{-22}{2}=~F\)
\({-11}~{=}~{F}\)